A brine is used to measure the absolute permeability of a core plug. The rock sample is 4 cm long and 3 cm 2 in cross section. The brine has a viscosity of 1.0 cp and is flowing a constant rate of 0.5 cm3/sec ( cube centimeter per second) under a 2.0 atm pressure differential.

Calculate the absolute permeability.

Respuesta :

Answer : The absolute permeability is, 0.111 darcys.

Explanation : Given,

Volumetric constant rate = [tex]0.5cm^3/s[/tex]

Cross section area = [tex]3cm^2[/tex]

Pressure = 2 atm

Viscosity = 1.0 cp

Length of rock = 4 cm

From the Darcy equation  we conclude that,

[tex]\text{Volumetric constant rate}=\frac{(\text{Absolute permeability}\times A\times P)}{\eta \times l}[/tex]

where,

A = cross section area

P = pressure

[tex]\eta[/tex] = viscosity

l = length of rock

Now put all the given values in the above formula, we get:

[tex]0.5cm^3/s=\frac{(\text{Absolute permeability}\times 3cm^2\times 2\text{ atm})}{1.0cp \times 4cm}[/tex]

[tex]\text{Absolute permeability}=0.111\text{ darcys}[/tex]

Therefore, the absolute permeability is, 0.111 darcys.

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