Answer: The correct alternative hypothesis for this analysis :
[tex]\H_a:\mu\neq\mu_2[/tex]
Step-by-step explanation:
Let [tex]\mu_1[/tex] be the mean of scores before beginning the program and  [tex]\mu_2[/tex] be the mean of scores after beginning the program .
Since, The study wanted to test whether there was a difference between before and after scores.
Also, the null hypothesis always takes equal sign and alternative hypothesis is just opposite of it, thus the null and alternative hypothesis will be :-
[tex]H_0 : \mu_1=\mu_2\\\\H_a:\mu\neq\mu_2[/tex]