Answer : The molar concentration of [tex]N_2O_4[/tex] is, [tex]5.1\times 10^{-7}M[/tex]
Explanation : Given,
Equilibrium constant = [tex]4.9\times 10^{3}[/tex]
Concentration of [tex]NO_2[/tex] = 0.050 M
The balanced equilibrium reaction is,
[tex]N_2O_4(g)\rightleftharpoons 2NO_2(g)[/tex]
The expression of equilibrium constant for the reaction will be:
[tex]K_c=\frac{[NO_2]^2}{[N_2O_4]}[/tex]
Now put all the values in this expression, we get :
[tex]4.9\times 10^3=\frac{(0.050)^2}{[N_2O_4]}[/tex]
[tex][N_2O_4]=5.1\times 10^{-7}M[/tex]
Therefore, the molar concentration of [tex]N_2O_4[/tex] is, [tex]5.1\times 10^{-7}M[/tex]
