Answer:
R = 0.27 ohm
i = 11.25 A
Explanation:
Resistance of a given cylindrical rod is
[tex]R = \rho \frac{L}{A}[/tex]
here we know that
[tex]\rho = \frac{1}{3 \times 10^4} = 3.33 \times 10^{-5} ohm-m[/tex]
Now we have
[tex]R = (3.33 \times 10^{-5})\times \frac{4 \times 10^{-3}}{0.5 \times 10^{-6}}[/tex]
[tex]R = 0.27 ohm[/tex]
now we know by ohm's law
[tex]\Delta V = i R[/tex]
[tex]14 - 11 = i ( 0.27)[/tex]
[tex]i = 11.25 A[/tex]