Answer: The amount of heat absorbed by aluminium is 2.271 kJ.
Explanation:
To calculate the amount of heat absorbed or released, we use the equation:
[tex]Q= m\times c\times \Delta T[/tex]
Q = heat absorbed = ?
m = mass of aluminium = 55.5 g
c = specific heat capacity of aluminium = 0.930 J/g ° C
Putting values in above equation, we get:
[tex]\Delta T={\text{Change in temperature}}=(67-23)^oC=44^oC[/tex]
[tex]Q=55.5g\times 0.930J/g^oC\times 44^oC[/tex]
Q = 2271.06 Joules
Converting this into kilo joules, we use the conversion factor:
1 kJ = 1000 J
So, 2271.06 J will be equal to 2.271 kJ
Hence, the amount of heat absorbed by aluminium is 2.271 kJ.
