Answer with explanation:
Pre-image =Rectangle EFGH
Image = Rectangle E'F'G'H'
Stretch Factor = 2.5
Coordinates of Point H= (-2,0)
If Coordinate of any point is (x,y) and it is stretched by a factor of k , then coordinate of that point after stretching = (k x , k y).
So, Coordinates of Point H' will be=(-2×2.5,0×2.5)
= (-5,0)
Answer: (-5,0)
Step-by-step explanation:
Given : Square EFGH stretches vertically by a factor of 2.5 to create rectangle E?F?G?H?.
The square stretches with respect to the x-axis such that the point H is located at (-2, 0).
Since , we know that to find the coordinate of image , we multiply the scale factor to the coordinate of pre-image.
Then , the coordinate of H? is given by :-
[tex](-2\times2.5, 0\times2.5)=(-5,0)[/tex]
