Respuesta :
Answer:
[tex]F_{applied} = 45.8 N[/tex]
Explanation:
When maximum force is applied on the crate along the plane so that it will not move then in that case friction force and component of the weight of the crate is along the plane opposite to the applied force
So here we will have
[tex]mgsin\theta + F_f = F_{applied}[/tex]
now we know that
[tex]F_f = \mu F_n[/tex]
also we know that
[tex]F_n = mg cos\theta[/tex]
so we will have
[tex]F_f = \mu ( mg cos\theta)[/tex]
now we will have
[tex]mg sin\theta + \mu (mg cos\theta) = F_{applied}[/tex]
[tex](5)(9.81)sin30 + (0.5)(5)(9.81)cos30 = F_{applied}[/tex]
so we will have
[tex]F_{applied} = 45.8 N[/tex]
