Twenty percent of all telephones of a certain type are submitted for service while under warranty. Of these, 60% can be repaired, whereas the other 40% must be replaced with new units. If a company purchases ten of these telephones, what is the probability that exactly two will end up being replaced under warranty?

Question

contestada

Respuesta :

windyyork windyyork · Answer 1 · 2019-07-11T11:01:21+02:00

Answer: Probability that exactly two will end up being replaced under warranty is 0.052.

Step-by-step explanation:

Since we have given that

Probability of all telephones are submitted for service = 20%

Probability of telephones get repaired = 60% of 20% = 0.12

Probability of telephones do not get repaired = 1-0.12 = 0.88

Probability of telephones get replaced = 40% of 20% = 0.80

Number of trials = 10

We need to find the probability that exactly two will end up being replaced under warranty.

We would use "Binomial distribution":

Let X be the number of replaced under warranty.

[tex]P(X=2)^{10}C_2(0.12)^2(0.88)^8=0.052[/tex]

Hence, Probability that exactly two will end up being replaced under warranty is 0.052.