Could anyone answer and also provide explanation.
Answer:
b
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
(a)
2x + 3y = 1 ( subtract 2x from both sides )
3y = - 2x + 1 ( divide all terms by 3 )
y = - [tex]\frac{2}{3}[/tex] x + [tex]\frac{1}{3}[/tex] ← in slope- intercept form
with y- intercept c = [tex]\frac{1}{3}[/tex] ← does not pass through the origin
(b)
2x + 3y = 0 ( subtract 2x from both sides )
3y = - 2x + 0 ( dividing all sides by 3 ), gives
y = - [tex]\frac{2}{3}[/tex] x + 0 ← in slope- intercept form
with y- intercept c = 0 ← passes through the origin
(c)
2x + 3y = 6 ( subtract 2x from both sides )
3y = - 2x + 6 ( divide all terms by 3 )
y = - [tex]\frac{2}{3}[/tex] x + 2
with y- intercept c = 2 ← does not pass through the origin