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05-07-2019
Mathematics

contestada

sin4θ - sin2θ = _____

2cos3θcosθ
2cos3θsinθ
2sin3θcosθ
2sin3θsinθ

Respuesta :

Аноним Аноним

05-07-2019

Answer:

B. 2cos3θsinθ.

Step-by-step explanation:

Use the identity

sin x - sin y = 2 [cos(x + y)/2]sin [x - y)/2].

So we have:

sin4θ - sin2θ = 2 cos (4θ+2θ)/2 sin (4θ-2θ)/2

= 2cos3θsinθ.

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