Answer:
B) 2.18 m/s²
Explanation:
M = Original mass of earth
R = Original radius of earth
g = original acceleration due to gravity of earth = 9.8 m/s²
M' = New mass of earth = 2 M
R' = New radius of earth = 3 R
g = original acceleration due to gravity of earth = 9.8 m/s²
Original acceleration due to gravity of earth is given as
[tex]g=\frac{GM}{R^{2}}[/tex]
[tex]9.8 =\frac{GM}{R^{2}}[/tex] eq-1
g' = new acceleration due to gravity of earth
New acceleration due to gravity of earth is given as
[tex]g' =\frac{GM'}{R'^{2}}[/tex]
[tex]g' =\frac{G(2M)}{(3R)^{2}}[/tex]
[tex]g'=\left ( \frac{2}{9} \right )\frac{GM}{R^{2}}[/tex]
Using eq-1
[tex]g'=\left ( \frac{2}{9} \right )(9.8)[/tex]
g' = 2.18 m/s²