Answer:
a) Force must be applied to the input piston = 10N
b) The input piston moved by 7.5 m
Explanation:
a) For a hydraulic lift we have equation
[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]
F₁ = ?
d₁ = 10 cm = 0.1 m
F₂ = 250 N
d₂ = 50 cm = 0.5 m
Substituting
[tex]\frac{F_1}{\frac{\pi \times 0.1^2}{4}}=\frac{250}{\frac{\pi \times 0.5^2}{4}}\\\\F_1=10N[/tex]
Force must be applied to the input piston = 10N
b) We have volume of air compressed is same in both input and output.
That is A₁x₁ = A₂x₂
A is area and x is the distance moved
x₂ = 0.3 m
Substituting
[tex]\frac{\pi \times 0.1^2}{4}\times x_1=\frac{\pi \times 0.5^2}{4}\times 0.3\\\\x_1=7.5m[/tex]
The input piston moved by 7.5 m
