Answer:
Charge on each plate = 2.31 x 10⁻⁸ C
Explanation:
We have the equations
[tex]E=\frac{V}{d}\texttt{ and }V=\frac{Q}{C}[/tex]
Combining both equations
[tex]E=\frac{\left (\frac{Q}{C}\right )}{d}=\frac{Q}{Cd}[/tex]
We also have the equation for capacitance
[tex]C=\frac{\epsilon A}{d}[/tex]
That is
[tex]E=\frac{Q}{\frac{\epsilon A}{d}\times d}=\frac{Q}{\epsilon A}\\\\Q=\epsilon AE[/tex]
Substituting
[tex]Q=8.85\times 10^{-12}\times 31.5\times 10^{-4}\times 8.30\times 10^5=2.31\times 10^{-8}C[/tex]
Charge on each plate = 2.31 x 10⁻⁸ C