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Blacklash

Answer:

The capacitance is 11 F for half and fully charged capacitor.

Explanation:

Capacitance of capacitor is given by the expression

             [tex]C=\frac{\epsilon A}{d}[/tex]

Where ε is the  vacuum permittivity, A is the area of plates and d is the separation between plates.

So capacitance does not depend upon charge and potential. So capacitance fully and half charged capacitors are same.

Here the capacitance is 11 F for half and fully charged capacitor.

leena

Hi there!


[tex]\boxed{C = 11F}[/tex]

Even though C = Q/V, the capacitance is NEVER changed by the charge or voltage.

The only factors that change the capacitance of a capacitor are those related to its geometry or if a dielectric is inserted. We can look at some examples:

For a parallel plate capacitor:
[tex]C = \frac{\epsilon_0A}{d}[/tex]

C = Capacitance (F)

A = Area of plates (m²)
d = distance between plates (m)

For a spherical capacitor:
[tex]C = 4\pi \epsilon_0 (\frac{r_{outer}r_{inner}}{r_{outer} - r_{inner}}})[/tex]

Notice how the capacitance is strictly determined by its geometric properties. Therefore, changing the charge or voltage has no effect, so the capacitance will remain 11 F.

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