Answer:
Option B is the correct answer.
Explanation:
Thermal expansion
[tex]\Delta L=L\alpha \Delta T[/tex]
L = 1.2 meter
ΔT = 65 - 15 = 50°C
Thermal Expansion Coefficient for aluminum, α = 24 x 10⁻⁶/°C
We have change in length
[tex]\Delta L=L\alpha \Delta T=1.2\times 24\times 10^{-6}\times 50=1.44\times 10^{-3}m[/tex]
New length = 1.2 + 1.44 x 10⁻³ = 1.2014 m
Option B is the correct answer.
Answer:
B. 1.201386 meters
Explanation:
The length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters is 1.201386 meters.
