Answer:
Option C is the correct answer.
Explanation:
By Charles's law we have
V ∝ T
That is
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Here given that
V₁ = 0.20 cubic meter
T₁ = 333 K
T₂ = 533 K
Substituting
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{0.20}{333}=\frac{V_2}{533}\\\\V_2=\frac{0.20}{333}\times 533=0.3198m^3[/tex]
New volume of the gas = 0.3198 m³
Option C is the correct answer.
