Answer:
Frequency, f = 481.8 Hz
Explanation:
Given that,
Length of windpipe, l = 4.6 ft = 0.182 m
We need to find the lowest resonant frequency of this pipe at 33 degrees Celcius. Firstly, we will find the speed of sound at 33 degrees Celcius as :
[tex]v=331+0.6T[/tex]
[tex]v=331+0.6\times 33[/tex]
v = 350.8 m/s
At resonance, wavelength is equal to 4 times length of pipe i.e.
λ = 4 l
We need that, [tex]f=\dfrac{v}{\lambda}[/tex]
[tex]f=\dfrac{350.8\ m/s}{4\times 0.182\ m}[/tex]
f = 481.8 Hz
So, the resonant frequency of the windpipe is 481.8 Hz. Hence, this is the required solution.
