Respuesta :
Answer : The expression for the fugacity coefficient [tex]\ln \phi[/tex], for the mixture is, -0.3669.
Explanation : Given,
Fugacity coefficient of component 1 = 0.784
Fugacity coefficient of component 2 = 0.638
Mole fraction of component 1 = 0.4
First we have to calculate the mole fraction of component 2.
As we know that,
[tex]\text{Mole fraction of component 1}+\text{Mole fraction of component 2}=1[/tex]
[tex]\text{Mole fraction of component 2}=1-0.4=0.6[/tex]
Now we have to calculate the expression for the fugacity coefficient [tex]\ln \phi[/tex].
Expression used :
[tex]\ln \phi=X_1\ln \phi_1+X_2\ln \phi_2[/tex]
where,
[tex]\phi[/tex] = fugacity coefficient
[tex]\phi_1[/tex] = fugacity coefficient of component 1
[tex]\phi_2[/tex] = fugacity coefficient of component 2
[tex]X_1[/tex] = mole fraction of of component 1
[tex]X_2[/tex] = mole fraction of of component 2
Now put all the give values in the above expression, we get:
[tex]\ln \phi=0.4\times \ln(0.784)+0.6\times \ln(0.638)[/tex]
[tex]\ln \phi=-0.3669[/tex]
Therefore, the expression for the fugacity coefficient [tex]\ln \phi[/tex], for the mixture is, -0.3669.