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If the fugacity coefficient of the components of a binary mixture are = 0.784, and =0.638 and mole fraction of component 1 is 0.4, write down and expression for the fugacity coefficient Inp, for the mixture.

Respuesta :

Answer : The expression for the fugacity coefficient [tex]\ln \phi[/tex], for the mixture is, -0.3669.

Explanation : Given,

Fugacity coefficient of component 1 = 0.784

Fugacity coefficient of component 2 = 0.638

Mole fraction of component 1 = 0.4

First we have to calculate the mole fraction of component 2.

As we know that,

[tex]\text{Mole fraction of component 1}+\text{Mole fraction of component 2}=1[/tex]

[tex]\text{Mole fraction of component 2}=1-0.4=0.6[/tex]

Now we have to calculate the expression for the fugacity coefficient [tex]\ln \phi[/tex].

Expression used :

[tex]\ln \phi=X_1\ln \phi_1+X_2\ln \phi_2[/tex]

where,

[tex]\phi[/tex] = fugacity coefficient

[tex]\phi_1[/tex] = fugacity coefficient of component 1

[tex]\phi_2[/tex] = fugacity coefficient of component 2

[tex]X_1[/tex] = mole fraction of of component 1

[tex]X_2[/tex] = mole fraction of of component 2

Now put all the give values in the above expression, we get:

[tex]\ln \phi=0.4\times \ln(0.784)+0.6\times \ln(0.638)[/tex]

[tex]\ln \phi=-0.3669[/tex]

Therefore, the expression for the fugacity coefficient [tex]\ln \phi[/tex], for the mixture is, -0.3669.

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