Answer:
The partial pressure of component A and B is 75 kPa and 25kPa respectively.
Explanation:
Total pressure of ideal gas mixture = 100kPa
Mole fraction of component B, [tex]\chi_B= 0.25[/tex]
Mole fraction of component A ,[tex]\chi_A[/tex]
As we know sum of all mole fraction in a mixture is equal to zero.
[tex]\chi_A+\chi+B=1[/tex]
[tex]\chi_A=1-\chi_B=1-0.25=0.75[/tex]
For partial pressure of each component we will apply Dalton's law of partial pressure:
[tex]p^{o}_i=p_{total}\times \chi_i[/tex]
Partial pressure of component a in a mixture:
[tex]p^{o}_A=p\times \chi_A=100kPa\times 0.75=75 kPa[/tex]
Partial pressure of component a in a mixture:
[tex]p^{o}_B=p\times \chi_B=100kPa\times 0.25=25 kPa[/tex]
