Answer:
[tex]T = 308.6 ^0 C[/tex]
Explanation:
Here by ideal gas equation we can say
[tex]PV = nRT[/tex]
now we know that pressure is kept constant here
so we will have
[tex]V = \frac{nR}{P} T[/tex]
since we know that number of moles and pressure is constant here
so we have
[tex]\frac{V_2}{V_1} = \frac{T_2}{T_1}[/tex]
now we know that initial temperature is 17.8 degree C
and finally volume is doubled
So we have
[tex]\frac{2V}{V} = \frac{T_2}{(273 + 17.8)}[/tex]
so final temperature will be
[tex]T_2 = 581.6 k[/tex]
[tex]T_2 = 308.6 ^o C[/tex]
