Answer:
Energy density = 0.0831 J/m³
Explanation:
Energy density of a capacitor is given by the expression
[tex]u=\frac{1}{2}\epsilon E^2[/tex]
We have electric field ,
[tex]E=\frac{V}{d}=\frac{480}{3.5\times 10^{-3}}=1.37\times 10^5V/m[/tex]
Here there is no dielectric
So energy density,
[tex]u=\frac{1}{2}\epsilon_0 E^2=\frac{1}{2}\times 8.85\times 10^{-12} \times (1.37\times 10^5)^2=8.31\times 10^{-2}=0.0831 J/m^3[/tex]
Energy density = 0.0831 J/m³
