Respuesta :
Answer:
The value of R and the internal resistance of the battery are 10.6 ohm and 2.45 ohm
Explanation:
Given that,
Emf of battery = 15.0 V
Voltage = 12.2 V
Power = 14.0 W
(a). We need to calculate the value of R
Using formula of power
[tex]P=IV[/tex]
[tex]P=\dfrac{V^2}{R}[/tex]
[tex]R=\dfrac{V^2}{P}[/tex]
Where, R = resistance
P = power
V = voltage
Put the value into the formula
[tex]R =\dfrac{(12.2)^2}{14.0}[/tex]
[tex]R=10.6\ \Omega[/tex]
(b). We need to calculate the internal resistance of the battery
Firstly we calculate the current
Using formula of current
[tex]I=\dfrac{V}{R}=\dfrac{P}{V}[/tex]
Put the value of P and V into the formula
[tex]I =\dfrac{14}{12.2}[/tex]
[tex]I=1.14\ A[/tex]
We calculate the internal resistance
Using formula of emf
[tex]e-V=Ir[/tex]
[tex]r =\dfrac{e-V}{I}[/tex]
Put the value into the formula
[tex]r=\dfrac{15.0-12.2}{1.14}[/tex]
[tex]r = 2.45\ \Omega[/tex]
Hence, The value of R and the internal resistance of the battery are 10.6 ohm and 2.45 ohm
