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A force of 500 N is applied to a hydraulic jack piston that is 0.2 m in diameter. If the piston that supports the load has a diameter of 2.0 m, approximately how much mass can be lifted by the jack? Ignore any difference in height between the pistons.

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Answer:

50,000 N

Explanation:

d = 0.2 m, r = 0.1 m,  f = 500 N,

D = 2 m, R = 1 m

Let F be the weight lifted by the jack.

By use of Pascal's law

f/a = F / A

F = f x A / a

F = 500 x 3.14 x 1 x 1 / (3.14 x 0.1 x 0.1)

F = 50,000 N

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