Respuesta :
Answer:
Charge on least sphere, q = 570 nC
Explanation:
It is given that,
Two small plastic spheres are given positive electrical charges. The distance between the spheres, r = 30 cm = 0.3 m
The repulsive force acting on the spheres, F = 0.13 N
If one sphere has four times the charge of the other.
Let charge on other sphere is, q₁ = q. So, the charge on first sphere is, q₂ = 4 q. The electrostatic force is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
[tex]0.13=9\times 10^9\times \dfrac{q\times 4q}{(0.3\ m)^2}[/tex]
[tex]q^2=\dfrac{0.13\times (0.3)^2}{9\times 10^9\times 4}[/tex]
[tex]q=5.7\times 10^{-7}\ C[/tex]
q = 570 nC
So, the charge on the least sphere is 570 nC. Hence, this is the required solution.
