on a day when the speed of sound in air is 340 m/s a bat emits a shriek whose echo returns to it 0.0250 seconds later. How far away is the mosquito that reflects back the shriek?

Respuesta :

Answer:

The distance of the mosquito from the bat is 4.25 m.

Explanation:

Given that,

Speed of sound in air v= 340 m/s

Time t = 0.0250 second

Let d be the distance of the mosquito from the bat.

The distance traveled by the sound when the echo heard is 2d.

We need to calculate the distance

Using formula of  distance

[tex]v = \dfrac{2d}{t}[/tex]

Put the value into the formula

[tex]v = \dfrac{2d}{25\times10^{-3}}[/tex]

[tex]d =\dfrac{25\times10^{-3}\times340}{2}[/tex]

[tex]d=4.25\ m[/tex]

Hence, The distance of the mosquito from the bat is 4.25 m.

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