Respuesta :
Answer:
The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.
Explanation:
Given that,
Mass of aircraft = 10000 kg
Speed = 620 km/h = 172.22 m/s
Altitude = 10 km = 1000 m
We calculate the change in potential energy
[tex]\Delta P.E=mg(h_{2}-h_{1})[/tex]
[tex]\Delta P.E=10000\times9.8\times(10000-0)[/tex]
[tex]\Delta P.E=10000\times9.8\times10000[/tex]
[tex]\Delta P.E=980000000\ J[/tex]
[tex]\Delta P.E=980\ MJ[/tex]
For g = 10 m/s²,
The change in potential energy will be 1000 MJ.
We calculate the change in kinetic energy
[tex]\Delta K.E=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)[/tex]
[tex]\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2-0^2)[/tex]
[tex]\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2)[/tex]
[tex]\Delta K.E=148298642\ J[/tex]
[tex]\Delta K.E=148.3\ MJ[/tex]
For g = 10 m/s²,
The change in kinetic energy will be 150 MJ.
Hence, The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.
