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In a hydraulic garage lift, the small piston has a radius of 5.0 cm and the large piston has a radius of 1.50 m. What force must be to the small piston in order to lift a Zamboni weighing 200,000 N on the large piston?

Respuesta :

Answer:

222.22 N

Explanation:

r = 5 cm = 0.05 m, R = 1.5 m, f = ? , F = 200,000 N

Use pascal's law

F / A = f / a

F / 3.14 x R^2 = f / 3.14 x r^2

F / R^2 = f / r^2

f = F x r^2 / R^2

f = 200000 x 0.05 x 0.05 / (1.5 x 1.5)

f = 222.22 N

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