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Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?

x2(4x + 1) – 2(4x + 1)
x2(4x – 1) + 2(4x – 1)
4x2(x + 2) – 1(x + 2)
4x2(x – 2) – 1(x – 2)

Respuesta :

apologiabiology
group first 2 and group last 2 and find factors and undistribute

(4x^3+x^2)+(-8x-2)
(x^2)(4x+1)+(-2)(4x+1)
x^2(4x+1)-2(4x+1)
answer is first one

The way to determine the factors of the given polynomial is; x²(4x + 1) - 2(4x + 1)

How to factorize polynomials?

We are given the polynomial;

4x³ + x² – 8x – 2

We can group the polynomial as follows;

(4x³ + x²) + (-8x - 2)

This grouping can be further factorized to get;

x²(4x + 1) + (-2)(4x + 1)

⇒ x²(4x + 1) - 2(4x + 1)

Read more about polynomials at; https://brainly.com/question/4142886

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