Answer:
(6^(n-1))/6
Step-by-step explanation:
The nth term of a geometric series is a function of the number n, the common ratio between each successive number in the series r and the first term a. This may be expressed mathematically as
= a(r)^n-1
Given the series,
a = 1/6,
r = T2/T1 = 1/1/6 = 6
The nth term
= (1/6)(6)^n-1
= (6^(n-1))/6
