lets solve the equation step by step:
(x + a)/ax = b/x
therefore, even if a = 0 and x = 0 turn out to be solutions for our equation, we cannot use them because our first equation would be undefined, thus, a =0, x = 0, would be extraneous solutions.
x ´a = ab
x = a(b ´- 1)
that would be the simplest equation, we have x in terms of a and b, meaning, we can solve the equation if we fix values for a and b, with a != 0 and x != 0
