What is the first step in writing f(x) = 3x2 + 6x – 8 in vertex form?
A.Factor out 3 from each term.
B.Form a perfect square trinomial by keeping the value of the C.function equivalent.
D.Write the trinomial as a binomial squared.
E.Factor out 3 from the first two terms.

The first step in writing f(x) = 3x² + 6x - 8 in vertex form is

E. Factor out 3 from the first two terms.

f(x) = 3x² + 6x - 8
f(x) = 3(x² + 2x) - 8
f(x) + 8 = 3(x² + 2x + __)
f(x) + 8 + 1 = 3(x² + 2x + 1)
f(x) + 9 = 3(x+1)²
f(x) = 3(x+1)² - 9

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Аноним Аноним · Answer 2 · 2019-05-16T17:30:31+02:00

Аноним Аноним

16-05-2019

Answer:

Factor out 3 from the first two terms.

Step-by-step explanation:

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What is the first step in writing f(x) = 3x2 + 6x – 8 in vertex form? A.Factor out 3 from each term. B.Form a perfect square trinomial by keeping the value of the C.function equivalent. D.Write the trinomial as a binomial squared. E.Factor out 3 from the first two terms.

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What is the first step in writing f(x) = 3x2 + 6x – 8 in vertex form?
A.Factor out 3 from each term.
B.Form a perfect square trinomial by keeping the value of the C.function equivalent.
D.Write the trinomial as a binomial squared.
E.Factor out 3 from the first two terms.