For this case we have that by definition, the perimeter of the trapezoid is given by the sum of its sides:
[tex]p = 9 + 18 + 11 + 12\\p = 50[/tex]
So, the perimeter is 50ft
On the other hand, the area is given by:
[tex]A = \frac {1} {2} (b_ {1} + b_ {2}) * h[/tex]
Where:
[tex]b_ {1}:[/tex] It is the largest base
[tex]b_ {2}:[/tex] It is the minor base
h: It's the height
Substituting the values:
[tex]A = \frac {1} {2} (18 + 12) * 9\\A = \frac {1} {2} (30) * 9\\A = \frac {1} {2} (270)\\A = 135[/tex]
So, the area of the trapezoid is [tex]135 \ ft ^ 2[/tex]
Answer:
the perimeter is 50ft
the area of the trapezoid is [tex]135 \ ft ^ 2[/tex]
