Answer:
Part 1) [tex](10x+15y)^{2}=(6x+9y)^{2}+(8x+12y)^{2}[/tex]
Part 2) The answer in the procedure
Step-by-step explanation:
Part 1)
we know that
Applying the Pythagoras Theorem
[tex]c^{2}=a^{2}+b^{2}[/tex]
we have
[tex]c=(10x+15y)[/tex]
[tex]a=(6x+9y)[/tex]
[tex]b=(8x+12y)[/tex]
substitute the values
[tex](10x+15y)^{2}=(6x+9y)^{2}+(8x+12y)^{2}[/tex]
Part 2) Transform each side of the equation to determine if it is an identity
[tex](10x+15y)^{2}=(6x+9y)^{2}+(8x+12y)^{2}\\ \\100x^{2}+150xy+225y^{2}=36x^{2}+54xy+81y^{2}+64x^{2}+96xy+144y^{2}\\ \\100x^{2}+150xy+225y^{2}=100x^{2}+150xy+225y^{2}[/tex]
The left side is equal to the right side
therefore
Is an identity