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A grocer wishes to blend two different coffee brands in order to make a blend of 400 pounds to sell at $3.00 a pound. If he uses a brand of coffee worth $2.70 a pound with another brand worth $3.20 a pound, how many pounds of each does he use?

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Step-by-step explanation:

Let's say x is the amount of $2.70/lb coffee and y is the amount of $3.20/lb coffee.

The total amount is:

x + y = 400

The total worth is:

2.70x + 3.20y = 3.00×400

2.7x + 3.2y = 1200

Solving the system of equations through substitution:

x = 400 - y

2.7 (400 - y) + 3.2y = 1200

1080 - 2.7y + 3.2y = 1200

0.5y = 120

y = 240

x = 160

The grocer uses 160 pounds of the $2.70/lb coffee and 240 pounds of the $3.20/lb coffee.

By solving a system of equations, we will see that they used 240 pounds of the $3.20 coffee and 160 pounds of the $2.70 coffee.

How to find the system of equations?

First, we need to define the variables, we can use:

  • x = pounds of the $2.70 coffee used.
  • y = pounds of the $3.20 coffee used.

We know that they make 400 pounds of the mixture, then:

x + y = 400

We also know that the price of the mixture is $3.00 per pound, then we will have that:

x*$2.70 + y*$3.20 = 400*$3.00

So the system of equations is:

x + y = 400

x*$2.70 + y*$3.20 = 400*$3.00

To solve this, we isolate one of the variables in one of the equations. For example, I will isolate x on the first equation:

x = 400 - y

Now we can replace that on the other equation to get:

(400 - y)*$2.70 + y*$3.20 = 400*$3.00

And solve this for y.

400*$2.70 - y*$2.70 + y*$3.20 = 400*$3.00

y*$0.50 = 400*$3.00 - 400*$2.70 = 400*$0.30

y = ( 400*$0.30)/$0.50 = 240

Then we have:

x = 400 - y = 400 - 240 = 160

This means that they used 240 pounds of the $3.20 coffee and 160 pounds of the $2.70 coffee.

If you want to learn more about systems of equations, you can read:

https://brainly.com/question/13729904

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