Drag the tiles to the correct boxes to complete the pairs. Match the one to one functions with their inverse functions.
Answer:
Part 1) [tex]f^{-1}(x)=3(x+17)/2[/tex] ----> [tex]f(x)=\frac{2x}{3}-17[/tex]
Part 2) [tex]f^{-1}(x)=x+10[/tex] -----> [tex]f(x)=x-10[/tex]
Part 3) [tex]f^{-1}(x)=\frac{x^{3}}{2}[/tex] ----> [tex]f(x)=\sqrt[3]{2x}[/tex]
Part 4) [tex]f^{-1}(x)=5x[/tex] ----> [tex]f(x)=x/5[/tex]
Step-by-step explanation:
Part 1) we have
[tex]f(x)=\frac{2x}{3}-17[/tex]
Find the inverse
Let
y=f(x)
[tex]y=\frac{2x}{3}-17[/tex]
Exchange the variables, x for y and y for x
[tex]x=\frac{2y}{3}-17[/tex]
Isolate the variable y
Adds 17 both sides
[tex]x+17=\frac{2y}{3}[/tex]
Multiply by 3 both sides
[tex]3(x+17)=2y[/tex]
Divide by 2 both sides
[tex]y=3(x+17)/2[/tex]
Let
[tex]f^{-1}(x)=y[/tex]
so
[tex]f^{-1}(x)=3(x+17)/2[/tex]
Part 2) we have
[tex]f(x)=x-10[/tex]
Find the inverse
Let
y=f(x)
[tex]y=x-10[/tex]
Exchange the variables, x for y and y for x
[tex]x=y-10[/tex]
Isolate the variable y
Adds 10 both sides
[tex]y=x+10[/tex]
Let
[tex]f^{-1}(x)=y[/tex]
so
[tex]f^{-1}(x)=x+10[/tex]
Part 3) we have
[tex]f(x)=\sqrt[3]{2x}[/tex]
Find the inverse
Let
y=f(x)
[tex]y=\sqrt[3]{2x}[/tex]
Exchange the variables, x for y and y for x
[tex]x=\sqrt[3]{2y}[/tex]
Isolate the variable y
elevated to the cube both sides
[tex]x^{3}=2y[/tex]
Divide by 2 both sides
[tex]y=\frac{x^{3}}{2}[/tex]
Let
[tex]f^{-1}(x)=y[/tex]
so
[tex]f^{-1}(x)=\frac{x^{3}}{2}[/tex]
Part 4) we have
[tex]f(x)=x/5[/tex]
Find the inverse
Let
y=f(x)
[tex]y=x/5[/tex]
Exchange the variables, x for y and y for x
[tex]x=y/5[/tex]
Isolate the variable y
Multiply by 5 both sides
[tex]y=5x[/tex]
Let
[tex]f^{-1}(x)=y[/tex]
so
[tex]f^{-1}(x)=5x[/tex]
The inverse of a function is shown in the picture we can calculate by interchanging the value of f(x) and x.
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have:
Functions are shown in the picture.
We have to find the inverse of a function.
[tex]\rm f(x) = \dfrac{2x}{3}-17[/tex]
To find the inverse of a function plug in the place of f(x)→x and x→f(x) ⁻¹
[tex]\rm x = \dfrac{2f^-^1(x)}{3}-17[/tex]
f(x) ⁻¹ = 3(x + 17)/2
Similarly, we can find the rest of the inverse of the function as follows:
f(x) = x - 10
f(x) ⁻¹ = x + 10
f(x) = ∛2x
f(x) ⁻¹ = x³/2
f(x) = x/5
f(x) ⁻¹ = 5x
Thus, the inverse of a function is shown in the picture we can calculate by interchanging the value of f(x) and x.
Learn more about the function here:
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