Answer:
The rectangle has the greater area
Is area is [tex]2\ cm^{2}[/tex] greater
Step-by-step explanation:
we know that
The area of rectangle is equal to
[tex]A=(6)*(4\frac{1}{2})=(6)*(\frac{9}{2})=27\ cm^{2}[/tex]
The area of the square is equal to
[tex]A=5^{2}=25\ cm^{2}[/tex]
therefore
The rectangle has the greater area
Find the difference
[tex]27\ cm^{2}-25\ cm^{2}=2\ cm^{2}[/tex]
Is area is [tex]2\ cm^{2}[/tex] greater
