Answer:
[tex]f(0)=7.07[/tex]
Step-by-step explanation:
We have the function [tex]f(x)=2(x)^2+5\sqrt{(x+2)}[/tex]
In this case we want to find the value of f0)
To find f(0) you must replace the x in the function with the number 0 and solve as shown below
[tex]f(0)=2(0)^2+5\sqrt{(0+2)}[/tex]
[tex]f(0)=0+5\sqrt{(0+2)}[/tex]
[tex]f(0)=5\sqrt{(2)}[/tex]
Therefore
[tex]f(0)=7.07[/tex]
