Answer:
Step-by-step explanation:
[tex]\dfrac{2}{3}(3x+9y)+\dfrac{1}{2}(4x-2y)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=\left(\dfrac{2}{3\!\!\!\!\diagup_1}\right)(3\!\!\!\!\diagup^1x})+\left(\dfrac{2}{3\!\!\!\!\diagup_1}\right)(9\!\!\!\!\diagup^3y})+\left(\dfrac{1}{2\!\!\!\!\diagup_1}\right)(4\!\!\!\!\diagup^2x})+\left(\dfrac{1}{2\!\!\!\!\diagup_1}\right)(-2\!\!\!\!\diagup^1y})\\\\=2x+(2)(3y)+2x-y=2x+6y+2x-y\qquad\text{combine like terms}\\\\=(2x+2x)+(6y-y)=4x+5y[/tex]