Answer:
[tex]\large\boxed{\left(-\dfrac{1}{2},\ -1\right)}[/tex]
Step-by-step explanation:
[tex]\text{The formula of a midpoint:}\\\\\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\================================\\\\A(1,\ -3),\ B(-2,\ 1)\\\\\text{Substitute:}\\\\x=\dfrac{1+(-2)}{2}=\dfrac{-1}{2}=-\dfrac{1}{2}\\\\y=\dfrac{-3+1}{2}=\dfrac{-2}{2}=-1[/tex]
Answer:
[tex](\frac{-1}{2} ,-1)[/tex]
Step-by-step explanation:
line segment AB has endpoints A(1,-3) and B(-2,1).
To find the midpoint of AB we use formula
[tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]
A(1,-3) is (x1,y1) , B(-2,1) is (x2,y2)
Plug in the values in the formula
[tex](\frac{1-2}{2} ,\frac{-3+1}{2} )[/tex]
[tex](\frac{-1}{2} ,\frac{-2}{2} )[/tex]
[tex](\frac{-1}{2} ,-1)[/tex]
