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05-06-2019
Chemistry

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What is the pressure of 1.9 mols of nitrogen gas in a 9.45 L tank and at a temperature of 228 K

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drpelezo drpelezo

06-06-2019

Answer:

P = 3.8 Atm = 2900 mmHg (2 sig.figs.)

Explanation:

PV = nRT => P = nRT/V = (1.9 moles)(0.08206LAtm/molK)(228K)/9.45L = 3.76 ~ 3.8 Atm x 760mmHg/Atm =2888 mmHg ~ 2900 mmHg (2 sig.figs.)

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