Answer:
decrease by a factor 10
Explanation:
The parallax angle of a close star is given by
[tex]p=\frac{1}{d}[/tex]
where
p is the parallax angle
d is the distance of the star from Earth, in parsecs
From the formula we see that the parallax angle is inversely proportional to the distance.
In this problem, the distance of the star is increased by a factor 10:
d' = 10 d
so the new parallax angle would be
[tex]p'=\frac{1}{10 d}=\frac{1}{10}\frac{1}{d}=\frac{p}{10}[/tex]
So, the parallax angle would decrease by a factor 10.
