A constant eastward horizontal force of 70. newtons is applied to a 20.-kilogram crate moving toward the east on a level floor. If the frictional force on the crate has a magnitude of 10. newtons, what is the magnitude of the crate’s acceleration?

Respuesta :

Answer:

[tex]3 m/s^2[/tex]

Explanation:

Newton's second law states that:

[tex]\sum F = ma[/tex]

where

[tex]\sum F[/tex] is the resultant of the forces acting on an object

m is the mass of the object

a is the acceleration

In this case we have two forces:

F = +70 N (east direction) is the horizontal push

Ff = -10 N (west direction) is the frictional force

so the net force is

[tex]\sum F=70 N - 10 N = 60 N[/tex]

We also know the mass of the crate

m = 20 kg

So we can find the acceleration

[tex]a=\frac{sum F}{m}=\frac{60 N}{20 kg}=3 m/s^2[/tex]

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