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A pot of stew is placed on a stove to heat. The temperature of the liquid reaches 170°F, and then the pot is taken off the burner and placed on a kitchen counter. The temperature of the air in the kitchen is 76°F.

If k = 0.34, the temperature of the liquid after 7 hours will be

ºF. (Hint: Use Newton’s cooling model.)

Respuesta :

luisejr77

Answer:

[tex]T =84.7\°F[/tex]

Step-by-step explanation:

Newton's cooling model is:

[tex]T(t) =T_0 + (T_i-T_0)e^{-kt}[/tex]

Where

t is the time in hours

[tex]T_0[/tex] is the ambient temperature

[tex]T_i[/tex] is the initial temperature of the body

[tex]k=0.34[/tex]

We know that:

[tex]T_0=76\°F[/tex]

[tex]T_i=170\°F[/tex]

Then after 7 hours the temperature of the liquid will be:

[tex]T(7) =76 + (170-76)e^{-0.34(7)}[/tex]

[tex]T =84.7\°F[/tex]

Answer:

84.7 IS CORRECT

Step-by-step explanation:

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