Respuesta :

kudzordzifrancis

Answer:

B. 0.43, -0.43

Step-by-step explanation:

The given equation is

[tex]-2=3-7\sqrt[5]{x^2}[/tex]

Combine similar terms to get:

[tex]-2-3=-7\sqrt[5]{x^2}[/tex]

[tex]-5=-7\sqrt[5]{x^2}[/tex]

[tex]\sqrt[5]{x^2}=\frac{5}{7}[/tex]

[tex]x^2=(\frac{5}{7})^5[/tex]

[tex]x^2=\frac{3125}{16807}[/tex]

[tex]x=\pm \sqrt{\frac{3125}{16807}}[/tex]

[tex]x=\pm 0.43[/tex]

[tex]x=0.43[/tex] or [tex]x=-0.43[/tex]

The correct answer is B.

frika

Answer:

B

Step-by-step explanation:

First subtract 3 from the equation:

[tex]-2-3=3-7\sqrt[5]{x^2}-3\\ \\-5=-7\sqrt[5]{x^2}[/tex]

Now divide the equation by -7:

[tex]\sqrt[5]{x^2}=\dfrac{5}{7}[/tex]

Now raise the equation to the 5th power:

[tex]x^2=\left(\dfrac{5}{7}\right)^5[/tex]

Take square root:

[tex]x=\pm \sqrt{\left(\dfrac{5}{7}\right)^5} =\pm \dfrac{25}{49}\sqrt{\dfrac{5}{7}} \\ \\x_1\approx 0.43\\ \\x_2\approx -0.43[/tex]

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