which is the axis of symmetry of a parabola with equation x^2=-4y?
Answer:
x = 0
Step-by-step explanation:
Given
x² = - 4y ( divide both sides by - 4 )
y = - [tex]\frac{1}{4}[/tex] x²
Which is a parabola opening vertically down with it's vertex at (0, 0) and symmetrical about the y- axis
Hence equation of axis of symmetry is x = 0