Answer:
No
Explanation:
Let's assume the gas pressure is constant. Then we can use Charle's law, which states that the volume of the gas is proportional to the absolute temperature (in Kelvin):
[tex]\frac{V}{T}=const.[/tex]
This can be rewritten as
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where we have
[tex]T_1 = 100^{\circ}+273 =373 K[/tex] is the initial temperature of the gas
[tex]T_2 = 50^{\circ}+273 =323 K[/tex] is the final temperature of the gas
Re-arranging the previous equation, we find
[tex]V_2=V_1 \frac{T_2}{T_1}=V_1 \frac{323 K}{373 K}=0.87 V_1[/tex]
so, the volume of the gas decreases by a factor 0.87.
