Respuesta :

|x-4| <3

=>. x-4<3 or -(x-4)<3

=>. x-4<3 or x+4>3

=>. x<7 or x>1

So solution is x>1 & x<7. =x€(1,7)

Hope it helps...

Regards,

Leukonov/Olegion.

Answer:

The solution to the given inequality is:

              [tex]1<x<7[/tex] i.e. in the interval form it is given by: (1,7)

Step-by-step explanation:

We are given a inequality in term of variable x as follows:

          [tex]|x-4|<3[/tex]

Now, we know that any inequality with modulus function is opened as follows:

If

[tex]|x-a|<b[/tex]

Then we have:

[tex]-b<x-a<b[/tex]

i.e. we may write it as:

[tex]a-b<x<a+b[/tex]

Here in the given expression we have:

a=4 and b=3

Hence, the solution is given by:

[tex]4-3<x<4+3\\\\i.e.\\\\1<x<7[/tex]

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