5A. The current that flowing through the circuit with a lightbulb of 22Ω connected to a voltage source of 110V is 5A.
The key to solve this problem is using Ohm's Law equations V = I*R, where V is the voltage drop, I is the current that flow through the element and R its resistance.
Clear I from the equation above:
I = V/R
With V = 110V, and R(lightbulb) = 22Ω
I = 110V/22Ω = 5A
