Answer:
[tex]2.41\cdot 10^{13}Hz, 1.24\cdot 10^{-5}m[/tex]
Explanation:
The energy of the photon must be equal to 0.1 eV, so let's convert this value into Joules first:
[tex]E=0.1 eV \cdot 1.6\cdot 10^{-19} J=1.6\cdot 10^{-20}J[/tex]
The energy of the photon is related to its frequency by
[tex]E=hf[/tex]
where h is the Planck constant and f is the frequency. Substituting,
[tex]f=\frac{E}{h}=\frac{1.6\cdot 10^{-20}J}{6.63\cdot 10^{-34}Js}=2.41\cdot 10^{13}Hz[/tex]
And now we can find the wavelength of the photon, which is given by
[tex]\lambda=\frac{c}{f}[/tex]
where c is the speed of light. Substituting,
[tex]\lambda=\frac{3\cdot 10^8 m/s}{2.41\cdot 10^{13} Hz}=1.24\cdot 10^{-5}m[/tex]
