Respuesta :
Answer:
the answer is
n = 0.01336 mol
Explanation:
To determine the number of moles of a gas, we need to have an expression that relates the pressure, temperature and volume of the system. For simplification, we assume that this gas is ideal so we use the equation PV=nRT. We calculate as follows:
PV=nRT
n = PV / RT
n = 235000(1.48x10^-4) / (8.314)(40+273.15)
n = 0.01336 mol
Answer : The correct option is, (B) [tex]1.34\times 10^2mol[/tex]
Explanation :
To calculate the moles of nitrogen gas we are using ideal gas equation:
[tex]PV=nRT[/tex]
where,
P = pressure of nitrogen gas = 235 kPa = 2.319 atm
Conversion used : (1 atm = 101.325 kPa)
V = volume of nitrogen gas = [tex]148cm^3=148mL=0.148L[/tex]
Conversion used : (1 L= 1000 mL)
T = temperature of nitrogen gas = [tex]40.0^oC=273+40.0=313K[/tex]
R = gas constant = 0.0821 L.atm/mole.K
n = moles of nitrogen gas = ?
Now put all the given values in the ideal gas equation, we get:
[tex](2.319atm)\times (0.148L)=n\times (0.0821L.atm/mole.K)\times (313K)[/tex]
[tex]n=0.0134mol=1.34\times 10^2mol[/tex]
Therefore, the number of moles of nitrogen gas are, [tex]1.34\times 10^2mol[/tex]
